1. The problem statement, all variables and given/known data I am pretty confused with how to go about answering this question: Calculate the maximum lenth of conveyor which can be used to avoid the belt failing from stress, for an installation carrying 140 t/h up a gradient of 10 degrees, if the belt width is 1.1m, the speed is 1.7 metres per second, the belt uses an 8ply belting and the max working tension is 6 kN/m ply. theres a 2 drum drivehead with an angle of wrap of 400 degrees, the coefficient of grip is 0.2. Idler coefficients = 0.03 (when belt is empty) 0.04 (for materials) mass of mivong parts = 65 kg/m end pulleys etc= 35m of extra empty belt I have looked into the belt tension equation and put a lot of effort into it, but i'm really confused, any help in understanding it would be highly appreciated from a confused beginner! 2. Relevant equations Tb = 1.37*f*L*g*[2*mi+ (2*mb + mm)*cos (δ)] + (H*g*mm) Where, Tb is in Newton. f = Coefficient of friction L = Conveyor length in meters. Conveyor length is approximately half of the total belt length. g = Acceleration due to gravity = 9.81 m/sec2 mi = Load due to the idlers in Kg/m. mb = Load due to belt in Kg/m. mm = Load due to the conveyed materials in Kg/m. δ = Inclination angle of the conveyor in Degree. H = vertical height of the conveyor in meters. 3. The attempt at a solution I genuinely have no idea, i just can't understand what to do, it seems like a completely random task we've been provided What i do know is Tb will be somehow derived from the 7.3 kN/m ply Also, maybe the equation F1/F1= e to the power of mu x alpha where mu is coefficient of friction alpha is wrap angle Any input will be highly appreciated!