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Engineering
Mechanical Engineering
Checking My Gearbox RPM Calculations for Conveyors
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[QUOTE="Baluncore, post: 5793269, member: 447632"] 30 ft in 4.5 min = 6.667 ft per min = 80” per min. A 2” diam roller has 6.283” circumference. So roller will be at 12.733 RPM. How you get a 12:1 gearbox ratio I do not know. It depends on the motor RPM. A 1500 RPM motor will need a reduction of 1500 / 12.733 = 117.8 : 1 ratio. 28 feet in 20 sec = 84 ft per min = 1008” per min. 2" diameter roller has 6.283” circumference. So roller will be at 160.5 RPM. A 1500 RPM motor will need a reduction of 1500 / 160.5 = 9.35 : 1 ratio. [/QUOTE]
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Mechanical Engineering
Checking My Gearbox RPM Calculations for Conveyors
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