- #1
wildman
- 31
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Homework Statement
Find [tex] R(\tau) [/tex] if a) [tex]S(\omega) = \frac{1}{(4+\omega^2)^2} [/tex]
Homework Equations
I have given [tex] \frac{4}{4+\omega^2} [/tex] <==> [tex] e^{-2|\tau|} [/tex]
The Attempt at a Solution
So [tex] S(\omega) = \frac{1}{(4+\omega^2)^2}=
\frac{1}{16}\frac{4}{(4+\omega^2)}\frac{4}{(4+\omega^2)} [/tex][tex] R(\tau)= \frac{1}{16} e^{-2|\tau|} * e^{-2|\tau|} [/tex]
Where * is convolutionSo
[tex] R(\Tau) = \frac {1}{8}\int_{0}^{\infty} e^{-2(\tau-\alpha)} e^{-2\alpha} d\alpha [/tex]
But that turns out to be infinite. Does anyone have any idea where I went wrong?
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