Convolution of an indicator function

  • Thread starter henry22
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You have the limits reversed on the second one but other than that:

Yes!! Ta-Daaa!! :biggrin:

You have now successfully actually calculated a convolution integral. Now that you have done that you might enjoy an animated picture of a convolution, albeit with two different functions. But it is the same idea. The shaded area represents the value of the integral. Look here:

http://mathworld.wolfram.com/Convolution.html
I can't believe it!!

So can I just check I have understood it. So to find the integral I need to say how the limits change depending on whether x>0 or x<0 and then calculate the integral for each case?
 
  • #27
LCKurtz
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I can't believe it!!

So can I just check I have understood it. So to find the integral I need to say how the limits change depending on whether x>0 or x<0 and then calculate the integral for each case?
That's what it amounts to. Note that I did edit that last post; you still have a minor error that I didn't notice my last post.
 
  • #28
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That's what it amounts to. Note that I did edit that last post; you still have a minor error that I didn't notice my last post.
Thank for all your help, it's very much appreciated!!
 

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