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How do you do the convolution of
exp (x(n))*u(x(n)) and exp(x(n-1))*u(x(n-1))
where u(x) is the unit step function. Thanks.
exp (x(n))*u(x(n)) and exp(x(n-1))*u(x(n-1))
where u(x) is the unit step function. Thanks.
Because convolution is commutative,How do you do the convolution of
exp (x(n))*u(x(n)) and exp(x(n-1))*u(x(n-1))
where u(x) is the unit step function. Thanks.
Wait, the [itex]x(n)[/itex] is inside the [itex]u(x)[/itex]? That makes it difficult to do, unless you tell us something more about what [itex]x(n)[/itex] looks like.How do you do the convolution of
exp (x(n))*u(x(n)) and exp(x(n-1))*u(x(n-1))
where u(x) is the unit step function. Thanks.
You are right, the other approach will be maniopulate the equation with the properties of convolution.Wait, the [itex]x(n)[/itex] is inside the [itex]u(x)[/itex]? That makes it difficult to do, unless you tell us something more about what [itex]x(n)[/itex] looks like.
Are you sure it's not supposed to be just [itex]u(n)[/itex]?