(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

your 200 gram cup of tea is boiling hot. About how much ice should you add to bring it down to 65C? Ice is initially at -15C. The specific heat capacity of ice id .5cal/gC

3. The attempt at a solution

So the ice we add needs to absorb 7000 calories of heat.

Heat capacity is Q/T heat divided by change in temperature . And specific heat capacity is is heat capacity divided by mass.

So to heat the ice to 0 Celsius we have

15C(.5cal)/gC(x) + 65(x) + 80 cal/g(x) =7000 calories.

cleaning it up

(15)(.5)x+65x+80x=7000 in units of energy

the 80 comes from the latent heat for melting ice which is 80cal/gram

and x is the unknown mass of ice.

and i get that x=45.9 grams of ice.

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# Homework Help: Cooling a cup of tea with ice.

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