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the vertices of a triangle are 0, and the points A (a, 0) and B (0,a) where a>0.
the point P moves in the plane OAB such that OP square + AP square + BP square = k square, where k is a positive constant. show that k mst be bigger than (2/3)a X square root of 3
i tried. but cant even know how to start. any hints?
the point P moves in the plane OAB such that OP square + AP square + BP square = k square, where k is a positive constant. show that k mst be bigger than (2/3)a X square root of 3
i tried. but cant even know how to start. any hints?