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A copper pipe has an inside diameter of 6.720 cm and an outside diameter of 8.000 cm. What length of this copper pipe will have a resistance of 8.05 × 10-3 W?
so i am using the equation R=rho(L/A)
A=pi(d2-d1)^2/4 which is 1.29E-4 m
and for copper rho is 1.7E-8
so 8.05E-3=(1.7E-8)(L/1.29E-4)
then L=60.93 m
but this isnt right.
please help me where i am going wrong.
so i am using the equation R=rho(L/A)
A=pi(d2-d1)^2/4 which is 1.29E-4 m
and for copper rho is 1.7E-8
so 8.05E-3=(1.7E-8)(L/1.29E-4)
then L=60.93 m
but this isnt right.
please help me where i am going wrong.