- #1
CathyLou
- 173
- 1
Hi.
I'm completely stuck on the following question, and have no idea how to even start it.
Any help would be really appreciated.
The first four terms, in ascending powers of x, of the binomial expansion of (1 + kx)^n are
1 + Ax + Bx^2 + Bx^3 + ...,
where k is a positive constant and A,B and n are positive intgers.
(a) By considering the coefficients of x^2 and x^3, show that 3 = (n - 2)k.
Thank you.
Cathy
I'm completely stuck on the following question, and have no idea how to even start it.
Any help would be really appreciated.
The first four terms, in ascending powers of x, of the binomial expansion of (1 + kx)^n are
1 + Ax + Bx^2 + Bx^3 + ...,
where k is a positive constant and A,B and n are positive intgers.
(a) By considering the coefficients of x^2 and x^3, show that 3 = (n - 2)k.
Thank you.
Cathy