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Coriolis effect

  1. Aug 4, 2013 #1
    http://imgur.com/euMW6FO
    In the above question, why is coriolis acceleration in the positive eθ direction?. The system is rotating in an anti-clockwise direction, and in the er direction the velocity of the cam is
    radially outwards. Would this mean that the coriolis acceleration is to the right of this velocity and thus in the negitive eθ direction?
     
  2. jcsd
  3. Aug 4, 2013 #2
    The Coriolis acceleration is defined from the point of view in the co-rotating frame, and it would be ## -2 \dot{r} \dot{\theta} ##, against the rotation.
     
  4. Aug 5, 2013 #3

    A.T.

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    If unsure about the direction use the cross product definition:

    https://en.wikipedia.org/wiki/Coriolis_effect#Formula

    Then use the right-hand-rule. Or the left-hand-rule to account for the minus sign in the definition, or the right-hand-rule but swap the cross product operands.

    Which makes me wonder: Why do they write the definition in that order and add the minus sign? This seems to be a convention for all inertial forces in the rotating frame:

    https://en.wikipedia.org/wiki/Rotating_reference_frame#Newton.27s_second_law_in_the_two_frames

    Why not swap the operands, and drop the minus sign? Is it make it them look like the linear inertial force -ma?
     
  5. Aug 5, 2013 #4
    In the non-inertial frame, a distinction is made between the "apparent" acceleration, which is treated as the acceleration in Newton's second law for the rotating frame, and three other terms, which are considered the effect of inertial forces and are tossed over to the other side of Newton's second law.
     
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