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Cos^3(x)*Sin(x) Derivative!

  1. Oct 27, 2011 #1
    Help!
    I last did this kind of work years ago in university. Can som1 please help me with the derivative.
     
  2. jcsd
  3. Oct 27, 2011 #2
    I think the question is ((cosx)^3)*sin(x).Am I right?The formula for d(uv)/dx=u(dv/dx)+v(du/dx).And of course I think you need only formula.Do you need answer?
     
  4. Oct 27, 2011 #3

    Mark44

    Staff: Mentor

    It is against Physics Forums policy to provide answers to posters' questions.
     
  5. Oct 27, 2011 #4
    Thats it chain rule or something:


    d(uv)/dx=u(dv/dx)+v(du/dx)

    u=sin(x)
    v=cos^3(x)

    (dv/dx) = -3sin((x))cos^2(x)
    (du/dx) = cos(x)

    d(uv)/dx= -3sin^2(x)cos^2(x) + cos^4(x)

    Is this correct?
     
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