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Cos^3(x)*Sin(x) Derivative!

  • Thread starter CloDawg
  • Start date
  • #1
5
0
Help!
I last did this kind of work years ago in university. Can som1 please help me with the derivative.
 

Answers and Replies

  • #2
33
0
I think the question is ((cosx)^3)*sin(x).Am I right?The formula for d(uv)/dx=u(dv/dx)+v(du/dx).And of course I think you need only formula.Do you need answer?
 
  • #3
33,267
4,966
I think the question is ((cosx)^3)*sin(x).Am I right?The formula for d(uv)/dx=u(dv/dx)+v(du/dx).And of course I think you need only formula.Do you need answer?
It is against Physics Forums policy to provide answers to posters' questions.
 
  • #4
5
0
Thats it chain rule or something:


d(uv)/dx=u(dv/dx)+v(du/dx)

u=sin(x)
v=cos^3(x)

(dv/dx) = -3sin((x))cos^2(x)
(du/dx) = cos(x)

d(uv)/dx= -3sin^2(x)cos^2(x) + cos^4(x)

Is this correct?
 

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