# Cos(45 - v) = sin (v + 45) for all angles v?

1. Oct 11, 2004

### Maria

How can I prove that
cos(45 - v) = sin (v + 45) for all angles v? :uhh:

2. Oct 11, 2004

### TenaliRaman

expand LHS using cos(A-B) formula
expand RHS using sin(A+B) formula
show that they are equivalent

-- AI

3. Oct 11, 2004

### marlon

or use the fact that cos(x) = sin(90°-x).

ofcourse if you wanna prove the above relation you will have to follow to advice of TenaliRaman.

regards
marlon

4. Oct 11, 2004

### Maria

can one of you show me? I dont really knowwhere to begin? :shy:

5. Oct 11, 2004

### Zurtex

You have, cos(45° - v) = sin (v + 45°)

Now as said before you should be aware of the relationship, cos(x) = sin(90°-x). All you have to do with this is let x = 45° - v.

However if you work is in context of the addition of angles then:

$$\sin (A \pm B) = \sin A \cos B \pm \sin B \cos A$$

$$\cos (A \pm B) = \cos A \cos B \mp \sin A \sin B$$

Let A = 45° and B = v.

6. Oct 11, 2004

### Maria

so then I get:
sin(45+v) = sin 45 cos v + sin v cos 45
cos(45-v) = cos 45 cos v + sin 45 sin v

does this prove that cos(45-v) = sin(v+45)?

7. Oct 11, 2004

### Zurtex

Almost, what does cos 45° and sin 45° equal?

8. Oct 11, 2004

### Maria

0,7071?

So I dont have to write more that this?

I dont really think Ive got it yet..

Last edited by a moderator: Oct 11, 2004
9. Oct 11, 2004

### Zurtex

Correct me if I am wrong but both cos 45° and sin 45° are $$\frac{\sqrt{2}}{2}$$

Therefore:

$$\sin (45+v) = \frac{\sqrt{2}}{2} \cos v + \frac{\sqrt{2}}{2} \sin v$$
$$\cos (45-v) = \frac{\sqrt{2}}{2} \cos v + \frac{\sqrt{2}}{2} \sin v$$

Spot something simmilar? When proving things never ever ever ever ever ever ever ever ever ever ever ever round things off!

10. Oct 12, 2004

### Maria

I didn`t know that.. thanks a lot..

11. Oct 12, 2004

### Galileo

It's easier with sin(x) = cos(x-90).
cos(45-v)=cos(v-45) since the cosine is even.
cos(v-45)=sin(v+90-45)=sin(v+45)