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Cos(x): 8 in x's denominator

  1. Mar 11, 2007 #1
    I have (from a complex equation problem) found the following angles in the answers:

    5PI/8, 9PI/8, 13PI/8, 17PI/8

    In the same assignement I found sin(PI/8) = .5*sqrt(2-sqrt(2)) and I found the cos(PI/8) value by using standard trig. identities.

    Is there an easy way to use this result to find the cos and sin of the angles stated? (The assignement tells us to use the answer we found from sin(PI/8))

    I know I can find formulas for cos(5x) etc by using this method: http://library.thinkquest.org/C0110248/trigonometry/form3.htm

    But that is going to take ages up to cos(17x) !

    I think I've missed something here.

    Thanks
     
  2. jcsd
  3. Mar 11, 2007 #2

    arildno

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    Hmm.. 5/8-1/8=1/2, I think. And 17=16+1, if I'm not mistaken
     
  4. Mar 11, 2007 #3
    I'm not getting it... :P
     
  5. Mar 11, 2007 #4

    arildno

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    [tex]\frac{17\pi}{8}=\frac{16\pi}{8}+\frac{1\pi}{8}=2\pi+\frac{\pi}{8}[/tex]
    For example
     
  6. Mar 11, 2007 #5
    ah, thanks I get it!
     
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