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Cos(x) = cosh(x)?

  1. Mar 12, 2011 #1
    1. The problem statement, all variables and given/known data

    2. Relevant equations
    from the identities found on the internet:




    3. The attempt at a solution

    Assuming for the definition of cosh(x), if we take x as being equal to (ix), then surely this shows that cosh(x)=cos(x)? Can someone explain why this is wrong please? because i can't see it
  2. jcsd
  3. Mar 12, 2011 #2


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    It shows cosh(ix)=cos(x), not cosh(x)=cos(x). There's nothing wrong with that.
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