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## Homework Statement

The cosine of a vector is equal to the opposite over its magnitude.

## Homework Equations

The attempt at a solution[/b] the cosine is the ratio of the adjacent to the hypothenuse this is why i say it "came' is incorrect.

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- Thread starter Tiven white
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The cosine of a vector is equal to the opposite over its magnitude.

The attempt at a solution[/b] the cosine is the ratio of the adjacent to the hypothenuse this is why i say it "came' is incorrect.

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What exactly was the original question?

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That is the ?,its a true or falseWhat exactly was the original question?

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NascentOxygen

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What statement is true or false?That is the ?,its a true or false

Oh, I see. It's this statement that's being questioned:

The cosine of a vector is equal to the opposite over its magnitude.

Yes, it's an incorrect statement, as you pointed out.

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What statement is true or false?

If the cosine of a vector is its y component over its magnitude?

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NascentOxygen

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It's not the vector which has a cosine. It's only **angles** which have cosines.

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HallsofIvy

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If this really is the statement, I would not say it was either "true"## Homework Statement

The cosine of a vector is equal to the opposite over its magnitude.

## Homework Equations

The attempt at a solution

the cosine is the ratio of the adjacent to the hypothenuse this is why i say it "came' is incorrect.

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vela

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Just out of curiosity, what is

supposed to mean?this is why i say it "came' is incorrect.

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NascentOxygen

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Just out of curiosity, what is

[ C A M ]

supposed to mean?

cosine = adjacent ÷ magnitude ?

- #10

vela

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Wouldn't that be correct?

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NascentOxygen

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Clearly, OP is a little confused.Wouldn't that be correct?

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Clearly, OP is a little confused.

The question was asking whether the statement ' cosine means the y component of a vector over its magnitude'.

Is this true or false?

- #13

NascentOxygen

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Definitely false.The question was asking whether the statement ' cosine means the y component of a vector over its magnitude'.

Is this true or false?

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