- #1
alejandrito29
- 150
- 0
with the action [tex] \int (k(R- 2 \Lambda)+L_m) \sqrt{g} [/tex] the Einstein equation is:
[tex]R_{uv}-\frac{1}{2}R g_{uv}- \Lambda g_{uv} = k' T_{uv}[/tex]
How is the Einstein equation if [tex]\Lambda=\Lambda(x^u)[/tex]? with [tex]x^u[/tex] a coordinate
[tex]R_{uv}-\frac{1}{2}R g_{uv}- \Lambda g_{uv} = k' T_{uv}[/tex]
How is the Einstein equation if [tex]\Lambda=\Lambda(x^u)[/tex]? with [tex]x^u[/tex] a coordinate