- #1
nameVoid
- 241
- 0
y=sin2x bounded by x=0,x=pi,y=0 , revolved around the x-axis
cross section A=pi(sin2x)^2
taking u = sinx ; du=cosxdx
im unclear on how to proceed in this case where du needs to satisfy (cosx)^2
the problem hints to use a half angle formula
cross section A=pi(sin2x)^2
taking u = sinx ; du=cosxdx
im unclear on how to proceed in this case where du needs to satisfy (cosx)^2
the problem hints to use a half angle formula