Cotangent function integration problem

Benny
Messages
577
Reaction score
0
I was doing an integration question earlier on and I came across something that I would like to be cleared up. The question basically boiled down to:

[tex] - \left[ {\cot \left( \theta \right) + \theta } \right]_{\frac{\pi }{6}}^{\frac{\pi }{2}} = - \left[ {\frac{{\cos \left( \theta \right)}}{{\sin \left( \theta \right)}} + \theta } \right]_{\frac{\pi }{6}}^{\frac{\pi }{2}} [/tex]

Now if I just substitute the relevant values into the antiderivative it works out fine. However if I write the following I end up getting a 'weird' (I do not
know the right words to describe it :biggrin: ) answer(something involving 1/infinity).

[tex] - \left[ {\cot \left( \theta \right) + \theta } \right]_{\frac{\pi }{6}}^{\frac{\pi }{2}} = - \left[ {\frac{1}{{\tan \left( \theta \right)}} + \theta } \right]_{\frac{\pi }{6}}^{\frac{\pi }{2}} [/tex]

Can someone explain to me why this occurs? I can understand that when certain values are substituted in, 'weird' numbers appear but I cannot understand why the question works/does not work, depending on which way an expression is written(I am referring to the cotangent function), even though it is just the same thing. Any help would be good. I hope I was not unclear. :biggrin:
 
Last edited:
on Phys.org
That's because [itex]\frac{\pi}{2} [/tex] is the domain of cotangent (cot pi/2=0) and not in the domain of tangent (tan pi/2 does not exist).Taking this int consideration,at best u can do is set a limit for the 1/tangent.But again,why do that,when pi/2 is clearly in the domain on cotangent and the result works out fine?<br /> <br /> Daniel.[/itex]
 
Thanks for clearing that up for me.
 

Similar threads

Replies
3
Views
2K
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
11
Views
2K
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
1K
Replies
28
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K