- #1
- 195
- 1
In a QM textbook (Newton), I found the below expression for large x:
[itex]
coth(x)\cong 1+2e^{-2x}
[/itex]
I tried
[itex]
coth(x)=\frac{e^{x}+e^{-x}}{e^{x}-e^{-x}}=\frac{1+e^{-2x}}{1-e^{-2x}}
[/itex]
[itex]
coth(x)\cong 1+2e^{-2x}
[/itex]
I tried
[itex]
coth(x)=\frac{e^{x}+e^{-x}}{e^{x}-e^{-x}}=\frac{1+e^{-2x}}{1-e^{-2x}}
[/itex]