# Could someone check me on this?

OK, I have four forces in equilibrium

F1 = 50i N

e2 = -0.485i + 0.485j - 0.728k
e3 = -0.557i + 0.743j + 0.371k
e4 = -0.371i - 0.743j + 0.557k

I need to find the magnitudes of F2,F3,and F4

I got F2 = 373.67 N (this might be a + or -, not sure, thinking +)
F3 = 346.43 N
F4 = 102.44 N

I used the equilibrium in each direction (x,y,z) and then I had three equations with three unknowns.

If someone could confirm that or tell me where I messed up, that would be great. Thanks!

quasar987
Homework Helper
Gold Member
It's very tedious work to do manually. Hopefully for you, someone will check it using a math program. I suggest you get one of those and learn how to use it. Very usefull to check answers like this one.

I have Mathematica, but I don't know how I would check it on there. Any thoughts?

mukundpa
Homework Helper
If the body is in equilibrium under the action of no. of forces, then sum of their components in x,y and z direction separately is zero.

If the force is given in the form
F = Fx i + Fy j +Fz k then it means the Fx , Fy, Fz are components in the corresponding direction and the magnitude is given by sqrt(Fx^2 + Fy^2 + Fz^2)
need not to solve the equations if the values are given.

Last edited:
quasar987