# Could use some help [=

1. Sep 13, 2007

### motoxtremechick

hey guys im new to this thing but i really need some help so i thought i would try it out see how it goes..
so heres the problwm

light traveling at 3.0 times 10^8 m/sec requires 8.3 minutes to reach the earth. how far away is the sun?

my teacher is really picky about showing steps and units and equations =\

any help is greatly appreciated!!!

2. Sep 13, 2007

### Staff: Mentor

What's the basic relationship between distance, speed, and time? Don't forget to convert that time to seconds before calculating the distance.

3. Sep 13, 2007

### xRadio

light is in m/sec soo what do you think you should do first?

4. Sep 13, 2007

### motoxtremechick

yea thats where is started and converted it into 498 seconds
then since were using kinematics equations in class i thought i would use

d=Vit+1/2at^2
d= distance or delta x
and for acceration its delta V over delta t

im just way stuck and im not sure why

i got 1.2times 10^10th but i think its wrong

5. Sep 13, 2007

### Staff: Mentor

The speed of light is a constant--there's no acceleration.

6. Sep 13, 2007

### xRadio

alright lets see what you have:
d = ?
v = 3.0 times 10^8 m/sec
t = 498 seconds

using only v and t you are able to get d

7. Sep 13, 2007

### motoxtremechick

o wow..
i see
all i needed to do was convert it into seconds and then multiply the two huh?
so it would be 1.49times 10^11

8. Sep 13, 2007

### motoxtremechick

thanks so much for taking the time to help me out!

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