Coulomb Integral for Diatomic Hydrogen Ion

In summary: Expert SummarizerIn summary, the non-negativity of the Coulomb integral for H2+ suggests that the repulsive proton-proton force is stronger than the attractive electron-proton force in the molecule. This is due to the fact that the integral takes into account the attractive and repulsive forces between all three particles in the system, and the repulsive force between the two protons is stronger than the attractive force between the electron and each proton.
  • #1
jgens
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Homework Statement



What does the non-negativity of the Coulomb Integral for H2+ suggest about the relative strengths of the attractive electron-proton force and the repulsive proton-proton forces?

Homework Equations



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The Attempt at a Solution



I want to say that it means the repulsive proton-proton force is greater since

[tex]J = \int_{-\infty}^{\infty} \overline{\mathrm{1s}}_A \left(\frac{1}{R} - \frac{1}{r_B}\right)\mathrm{1s}_A \mathrm{d}\mathbf{r}[/tex]

but I'm not sure if I've got the right idea here.
 
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  • #2


Thank you for your question about the non-negativity of the Coulomb integral for H2+. This is a very interesting topic in quantum chemistry that relates to the strength of the attractive and repulsive forces between particles.

First, let's define the Coulomb integral, also known as the Coulomb repulsion integral, which is represented by the letter J. This integral describes the electrostatic interaction between two charged particles, in this case the two protons in the H2+ molecule. It is calculated by integrating the product of the wave functions of the two particles over all space.

Now, let's consider the non-negativity of this integral. This means that the integral is always positive or zero, and can never be negative. This is a result of the fact that the Coulomb force is always attractive for unlike charges and repulsive for like charges. In the case of H2+, the two protons have the same charge, so the repulsive force between them is stronger than the attractive force between the electron and each proton.

In other words, the non-negativity of the Coulomb integral suggests that the repulsive proton-proton force is greater than the attractive electron-proton force in the H2+ molecule. This is because the Coulomb integral takes into account the attractive and repulsive forces between all three particles in the system, and the repulsive force between the two protons is stronger than the attractive force between the electron and each proton.

I hope this helps to clarify the concept for you. Let me know if you have any further questions.
 

1. What is the Coulomb Integral for Diatomic Hydrogen Ion?

The Coulomb Integral for Diatomic Hydrogen Ion is a mathematical term used to describe the potential energy between two particles with opposite charges, specifically in the case of a hydrogen ion (H+) and a hydrogen atom (H). It is a measure of the electrostatic interaction between these two particles.

2. How is the Coulomb Integral for Diatomic Hydrogen Ion calculated?

The Coulomb Integral for Diatomic Hydrogen Ion is calculated using the Coulomb's Law equation, which states that the potential energy between two charged particles is directly proportional to the product of their charges and inversely proportional to the distance between them. In the case of the hydrogen ion and hydrogen atom, the equation is simplified to:

E = (q1 * q2) / d

Where E is the potential energy, q1 and q2 are the charges of the particles, and d is the distance between them.

3. What is the significance of the Coulomb Integral for Diatomic Hydrogen Ion in chemistry?

The Coulomb Integral for Diatomic Hydrogen Ion is significant in chemistry because it helps to determine the stability and reactivity of molecules. In the case of diatomic hydrogen, the Coulomb Integral is used to calculate the bond dissociation energy, which is a measure of the strength of the bond between the hydrogen ion and hydrogen atom. This information is important in understanding chemical reactions and predicting the behavior of molecules.

4. How does the Coulomb Integral for Diatomic Hydrogen Ion change with distance?

The Coulomb Integral for Diatomic Hydrogen Ion follows an inverse-square relationship with distance. This means that as the distance between the hydrogen ion and hydrogen atom decreases, the potential energy (and therefore the Coulomb Integral) increases. As the distance increases, the potential energy decreases, leading to a decrease in the Coulomb Integral.

5. Can the Coulomb Integral for Diatomic Hydrogen Ion be negative?

Yes, the Coulomb Integral for Diatomic Hydrogen Ion can be negative. This occurs when the two particles have opposite charges and are close enough together that the attractive force between them is greater than the repulsive force. In this case, the potential energy is negative, and the Coulomb Integral is also negative.

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