- #1
dancer2012
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Homework Statement
Two small pith balls, each of mass m = 12 g, are suspended by 1.2 m fine (so that we can neglect their mass in this problem) strings and are not moving. If the angle that each string makes with the vertical is θ = 42.6°, and the charges on the two balls are equal, what is that charge (in μC)?
Homework Equations
F(T)+F(g)+F(E)=0
F(Ty)=F(g)=mg
F(Tx)=k(q^2/r^2)
The Attempt at a Solution
I really don't know how to manipulate these formulas to find an answer. I know you find F(Ty) first, but then I don't know how to get F(Tx). I think I am missing a formula somewhere. Please Help Thank you