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Coulomb's Law - Calculating Net Force
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[QUOTE="haruspex, post: 4986942, member: 334404"] They only cancel out if all the distances plugged in are in metres and all the charges plugged in are in Coulombs. That's not strictly correct. Since F, q1, q2 and r are represented symbolically at this point, their units are unspecified in the equation. Therefore the units of the constant should be shown: F=(9x10[SUP]9[/SUP]) q1 q2 / r[SUP]2[/SUP] [B]Nm[SUP]2[/SUP]/C[SUP]2[/SUP][/B] When the values are plugged in: F=(9x10[SUP]9[/SUP]) (70μC)*(48μC) / r[SUP]2[/SUP] (Nm[SUP]2[/SUP]/C[SUP]2[/SUP]) =(9x10[SUP]9[/SUP]) 70*(48) / r[SUP]2[/SUP] (Nm[SUP]2[/SUP]/C[SUP]2[/SUP]) μC[SUP]2[/SUP] = (9x10[SUP]9[/SUP]) 70*(48) / r[SUP]2[/SUP] Nm[SUP]2[/SUP] (μC/C)[SUP]2[/SUP] = (9x10[SUP]9[/SUP]) 70*(48) / r[SUP]2[/SUP] Nm[SUP]2[/SUP] (10[SUP]-6[/SUP])[SUP]2[/SUP] = (9x10[SUP]-3[/SUP]) 70*(48) / r[SUP]2[/SUP] Nm[SUP]2[/SUP] = (9x10[SUP]-3[/SUP]) 70*(48) / (0.35m)[SUP]2[/SUP] Nm[SUP]2[/SUP] = (9x10[SUP]-3[/SUP]) 70*(48) / (0.35)[SUP]2[/SUP] N neonerd got that number for the case where the charges are 48 and 70 μC. [/QUOTE]
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Coulomb's Law - Calculating Net Force
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