apparently i got the correct answer for this problem to be 8.62*10^(-5) N but when I try doing it again, I get a different answer.(adsbygoogle = window.adsbygoogle || []).push({});

A particle of charge 4.96nC is placed at the origin of an xy-coordinate system, and a second particle of charge 2.02nC is placed on the positive x-axis at 3.96cm. A third particle, of charge 6.01nC is now placed at the point 3.96cm, 3.01cm.

Find the x-component of the total force exerted on the third charge by the other two. Use episilon_0=8.85×10-12C/N*m^2 for the permittivity of free space.

I first converted each charge and distance from nC to C and cm to m. Then I used the equation F=(1/4piEpisilon_0)*(|product of charges|/distance between charges^2) to determine the electric force converted on one charge by another charge. I then multiplied this F by cos(45) to find the total x-component. I do this but i'm not getting the same answer i got before. Can someone help me out?

PS: how would I find the y component of the force exerted on charge 3 by charge 2? Would it just be the Force of 2 on 3 multiplied sin(90)?

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# Homework Help: Coulomb's Law: forces between charges

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