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## Homework Statement

A rigid, insulating fiber runs along a portion of the y-axis; the fiber isnot free to move. Gravity acts downward (g = 9.81 m/s2).A charge Qa = -7 µC is fixed to the fiber at the origin. A bead with a hole drilled through its center is slipped over the fiber andis free to move along the fiber without friction. The mass of the bead is m = 250g and its charge is Qb. At equilibrium, the bead floats a distanceyb = 11 cm above the origin.

Calculate the charge on the bead.

## Homework Equations

Why isn't coulonmbs law working for me????

## The Attempt at a Solution

OK heres what i did

F = (KQa * Qb) / r^2

(absolute values for the charges)

(i got F by realizing that it must balance the opposing downward force (drew FBD)

so,

(.245)9.81 = (9.0*10^9) (7*10^-6)Qb / ((.011)^2)

So Qb comes to 4.71*10-9

=wrong for sum reason

Please help and THANKS!