I'm new in this forum, so i don't know if this is in the correct place.. 1. The problem statement, all variables and given/known data I got 3 charges q1= 2.0x10^-6C q2=8.0x10^-6C Q=4.0x10^-6C They're placed in the corners of a triangle like in this draw I have to know the force that q1 and q2 act on Q, the magnitude, and the direction 2. Relevant equations F=(kq1q2)/r2 for the angle which is 38.65 i do the tan-1 of .40/.50 3. The attempt at a solution Fq1Q=( (9x109 Nm2/c2) (2.0x10-6 C) (4.0x10-6C))/(.50m)2 Fq1Q= .288N So know i split in the components of X and Y right? x= .288(cos38.65) Y= .288 (sin38.65) x=.22N Y= .1798 Fq2Q=( (9x109 Nm2/c2) (8.0x10-6 C) (4.0x10-6C))/(.50m)2 Fq2Q= 1.152N x=1.152 (cos 38.65) Y=1.152 (sin38.65) x=.8999n y=.7119n Now for the magnitude x= .22+.899=1.119N y=-.1798+.7119= .5321N sqrt((1.119)2(.5321)2)= 1.311N as for the direction tan-1 = (.5321/1.119)= 25.43° so.. am I right? all sugetionts are really apreciated, tips and stuff.. hope anyone can help me sry if my descriptions are wrong, I'm from mexico and my english is not perfect:shy: if someone also could give me other exercises for practice... it will be perfect!