Look back at the Example in the Using Coulombs Law-Comparative Analysis section. Calculate the magnitude of F2 if both changes occurred simultaneously-that is, if the distance between the charges doubled and the size of once tripled, while the size of the other doubled.
This is the original example:
If the electrostatic force between two charges is 6.0 x 10^-8 N, what effect would each of the following changes have on the magnitude of the force?
1) the distance between the charges is doubled
2)One charge is doubled and the other is tripled
F2 = (6.0x10^-8 N)xr1 / (2r1)^2
= (6.0x10^-8 N) / 4
= 1.5 x 10^-8 N
F1/F2 = q1q2/q1q2
(6.0x10^-8 N)/F2 = q1q2 / (2q1)(3q2)
F2 = (6.0x10^-8N)(6)
= 3.6 x 10^-7 N
This is the solution to the example!!
The Attempt at a Solution
I can do the actually solution to this problem, but my only question is what are the values of q1 and q2 and r? Since they're literally exactly the same in both questions, does it mean that they all just double and triple from the original? Meaning r = 4r1, q1 = 6q1, q2 = 6q2
Does anyone have any suggestions?