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Introductory Physics Homework Help
Calculating Net Force and Electric Field Using Coulomb's Law - Homework Question
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[QUOTE="kurt1992, post: 4590826, member: 495779"] [h2]Homework Statement [/h2] This is the charge distribution:B | | | 2.0 m | | A------------C 2.0 m A = 2.0*10^-5 C B = -3.0*10^-5 C C = -3.0*10^-5 C a) Find the net force on the charge b) what is the net electric field acting on the charge[h2]Homework Equations[/h2] FE=kq1q2/r^2 electric field = Fnet/q [h2]The Attempt at a Solution[/h2] a) The charges acting on A are equal and at equal distance so they are then same. F_E=(9.0*10^9)(2.0*10^-5)(-3.0*10^-5)/2^2 F_E=5.4/4 F_E=1.35 N Each charge has a net force of 1.35 Newtons on charge 1. However, force is a vector quantity so the vectors have to have the same direction in order to add them. (The forces are the same so we can simply multiply the hypotenuse of the electric force by 2 to find the net force on particle 1. (F_E/cos45)(2)=Fnet 3.81838=Fnet Direction N45E (is this correct? my books solution to the problem involves adding x and y components which make a very confusion solution.) b) ε=3.81838/(2.0*10^-5) ε=190919 N/C [/QUOTE]
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Introductory Physics Homework Help
Calculating Net Force and Electric Field Using Coulomb's Law - Homework Question
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