A particle of mass 63 g and charge 59 [tex]\mu C[/tex] is released from rest when it is 71 cm from a second particle of charge -27 [tex]\mu C[/tex]. Determine the magnitude of the initial acceleration of the 63 g particle. Answer in units of m/s^2. I used Coulomb's Law, F= [tex] 1/4\pi \epsilon_o * (5.9 x10^-6 * -2.7 x 10^-6) / .71^2 [/tex] I know that E_o = 8.85 x 10^-12. Solving this gave me .284. Then I set it equal to ma. 63 a = .284 Solving for a gave me .00451 m/s^2. Can someone tell me what I'm doing wrong?