1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Coulomb's law

  1. Mar 31, 2012 #1
    1. The problem statement, all variables and given/known data

    see attachment

    2. Relevant equations



    3. The attempt at a solution

    Do you see the step where they go from (1.35keq2)/a2

    to 1.91keq2)/a2 ?

    I can't get that step. To my mind. If you square 1.35 then take its square root, you get 1.35 not 1.91
     

    Attached Files:

  2. jcsd
  3. Mar 31, 2012 #2
    [tex]\sqrt{1.35^2 \left (\frac{k_e q^2}{a^2} \right )^2 +1.35^2 \left (\frac{k_e q^2}{a^2} \right )^2}[/tex]
    [tex]\sqrt{\left (\frac{k_e q^2}{a^2} \right )^2(1.35^2 +1.35^2) }[/tex]
    [tex]\frac{k_e q^2}{a^2}\sqrt{1.35^2 +1.35^2 }[/tex]
    [tex]\frac{k_e q^2}{a^2}\sqrt{(2)(1.35^2)}[/tex]
    [tex]\frac{k_e q^2}{a^2}\sqrt{2}1.35[/tex]
    [tex]\frac{k_e q^2}{a^2}1.91[/tex]
     
  4. Mar 31, 2012 #3

    SammyS

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    attachment.php?attachmentid=45754&d=1333236363.png

    If you square 1.35 then multiply by 2, then take the square root of that result you do get 1.91, approximately.
     
  5. Mar 31, 2012 #4
    Roshan,

    Excellent answer. If only more math texts included as many steps as you do!!! I really appreciate it.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Coulomb's law
  1. Coulomb's law (Replies: 1)

  2. Coulomb's law (Replies: 8)

  3. Coulomb Law (Replies: 1)

Loading...