Two small nonconducting spheres have a total charge of 80 microC. When place 1.06 m apart, the force exerts on the other is 12 N and is repulsive. What is the charge of each. What if the force were attractive?(adsbygoogle = window.adsbygoogle || []).push({});

Given: k, F = 12 N if repulsive but F = -12 N if attractive, Q1 + Q2 = 8 x 10^-5 C, r = 1.06 m

Using Coulomb’s Law, isolate Q1Q2 .

Q1Q2 = 1.498 x 10^-9 C?

Then I thought I would use substitution for Q1 + Q2 = 8 x 10^-5 C and Q1Q2 = 1.498 x 10^-9 C.

But now I get a huge quadratic equation. Is this the correct method??

Thanks.

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# Homework Help: Coulomb’s Law

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