- #1

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I'm finding the arch length of a curve:

[tex] $\int_0^b \sqrt{1+sh^2(x/a)} dx$ [/tex]

How do i integrate this function?

[tex] $\int_0^b \sqrt{1+sh^2(x/a)} dx$ [/tex]

How do i integrate this function?

Last edited:

- Thread starter Madou
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- #1

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[tex] $\int_0^b \sqrt{1+sh^2(x/a)} dx$ [/tex]

How do i integrate this function?

Last edited:

- #2

CompuChip

Science Advisor

Homework Helper

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What do you mean by "count"?

What is "sh"?

If it is the hyperbolic sine: cosh^2 - sinh^2 = 1.

What is "sh"?

If it is the hyperbolic sine: cosh^2 - sinh^2 = 1.

- #3

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I think he meant "evaluate".

What do you mean by "count"?

- #4

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The derivative of sinh is cosh and the derivative of cosh is sinh

- #5

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It's a pity I can't edit the topic.I think he meant "evaluate".

- #6

CompuChip

Science Advisor

Homework Helper

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Exactly. Does this mean you have solved the problem?The derivative of sinh is cosh and the derivative of cosh is sinh

- #7

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Next step was to use the equation CC gave me.Does this mean you have solved the problem?

Thank you, guys.

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