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Countable union of Jordan sets is not always Jordan measurable

  1. Sep 23, 2016 #1
    1. The problem statement, all variables and given/known data

    Show that the countable union or countable intersection of Jordan measurable sets need not be Jordan measurable, even when bounded.
    3. The attempt at a solution
    For countable intersection, I think the rationals from 0 to 1 will work, each rational have jordan measure zero.
    But The jordan outer measure would be 1, because you would need to include the whole interval to contain all the rationals. For the countable intersection that seems more difficult. Im trying to think of a way to construct the vitali set using that. Well maybe for the intersection we take the unit interval [0,1] and shift it by that rationals of the form [itex] \frac{1}{2^n} [/itex]
     
  2. jcsd
  3. Sep 28, 2016 #2
    Thanks for the thread! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post? The more details the better.
     
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