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Counter flow heat exchangers

  1. Oct 21, 2014 #1
    1. The problem statement, all variables and given/known data

    Process water with a specific heat capacity of 4.182 kJ kg–1 K–1 flows at a rate of 0.050 kg s–1 through a heat exchanger where its temperature is increased from 16°C to 85°C. Heat is supplied by exhaust gases (mean specific heat capacity 1.075 kJ kg–1 K–1) which enter the heat exchanger at a temperature of 420°C. If the mass flowrate of the exhaust gases is 0.044 kg s–1, determine their outlet temperature


    2. Relevant equations

    ∆T=(TH2 –TC1)–(TH1 –TC2) ln⎛TH2 –TC1⎞

    ⎜ ⎟ ⎝TH1 –TC2⎠


    3. The attempt at a solution

    I understand the basis on how to calculate the Temperature difference and heat loss along with area however I am unsure on how to calculate the outlet hot temperature Th2 and how to rearrange this equation to find the outlet temp
    Any guidance or equations that may be of use would be much appreciated
     
  2. jcsd
  3. Oct 21, 2014 #2
    What is the rate of heat flow from the hot gas to the process water? This is the "heat load" of the heat exchanger. You can determine this directly from the flow rate and temperature change of the process water.

    Chet
     
  4. Oct 21, 2014 #3
    Hi Chet
    Thanks for your reply
    Would this be 0.05x(85-16)=3.45?
    Is this the heat capacity rate?
    Thanks
     
  5. Oct 21, 2014 #4
    You left out the heat capacity from your expression to calculate the heat load. The heat load is WCp(Tout-Tin).

    Chet
     
  6. Oct 21, 2014 #5
    Ok so it simply 3.45x4.182=14.4279
    Thanks
     
  7. Oct 22, 2014 #6
    Chet, please note the heat exchanger is a double pipe type and the fluids are in counter flow - not sure if this has an impact on which equations that were going to be used
    Thanks in advance
     
  8. Oct 22, 2014 #7
    You can figure that out yourself if you can articulate what is happening physically. Please give it a try.

    Chet
     
  9. Oct 22, 2014 #8
    Okay thanks for your help I will give it a go
     
  10. Oct 22, 2014 #9
    Hi Chet
    Thanks for the help with the heat exchanger question
    I would be grateful if you pointed me in the right direction on which method to use as I do not have the area, i could easily work the temp outlet hot out using the effectiveness method although I do not have the area. I am rather stuck and do not know which way to look
    Again thanks
     
  11. Oct 22, 2014 #10
    You would have to do that kind of analysis if you didn't know the inlet and outlet temperatures for one of the streams. But, in this problem, you do. So you can get the heat load, and you can get the outlet temperature of the other stream. If you were designing a heat exchanger, you would not be finished here. To design the heat exchanger, you would have to find the heat transfer area to make good on this heat load. You could use the method you alluded to in order to do this.

    Chet
     
  12. Nov 16, 2014 #11
    Hi
    this is my attempt

    Φ=qmc cpC (TC1-TC2) = qmH cpH (TH1-TH2)
    Therefore:
    Φ = qmc cpC (TC1-TC2)
    Φ = 0.050 x 4.184 x (85-16)
    Φ = 0.209 x 69
    Φ = 14.4W
    Now:
    14.4 =0.044 x 1.075 x (410 - TH2)
    14.4/0.044 x 1.075 = (410 - TH2)
    = 410 – 304
    TH2 = 106 degrees
     
  13. Nov 16, 2014 #12
    Looks good.

    Chet
     
  14. Nov 17, 2014 #13
    I believe it should be 420-305 which is 115 degrees
     
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