A club has only 8 women and 6 men as members. A team of 3 is to be chosen to represent the club. In how many ways can this be done if there is to be at least one woman on the team.
The Attempt at a Solution
I can do this 2 ways,
first 1w2m + 2w1m + 3m0m => (8c1)(6c2) + (8c2)(6c1) + (8c3)(6c0) =344
total- all men => (14c3) - (6c3) = 344
But the problem i cant get my head around is why this way doesnt work: (8c1)(13c2)
can some one please throw some light on this for me[/B]
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