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CP violation and Entropy

  1. Jul 28, 2015 #1
    Please help me with my confusion.
    My logic:
    1. CP violation causes direct T-violation
    2. T-violation breaks Kirchhoff's law of thermal radiation (imagine a rock in a thermal bath of T-violating particles, where absorption and emission rates are different). When I say "radiation", I don't mean photons, but any type of radiation.
    3. Such body in thermal equilibrium with environment will become hotter or colder than environment, depending on what is more probable - absorption or emission.
    4. !!!!????
     
  2. jcsd
  3. Jul 28, 2015 #2
    Will the rock become hotter or colder than the environment? Wouldn't the rate of absorption of T-violating particles equal the emission of T-violating antiparticles?
     
  4. Jul 29, 2015 #3
    No, because you are describing the CT symmetry, which is also violated.
     
  5. Jul 29, 2015 #4

    Demystifier

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    Transition probability in quantum physics depends on two factors. One factor is the probability amplitude, which is asymmetric for absorption/emission in T-violating processes. But the other factor which you might overlook is the phase-space factor; the transition to a larger phase space is more probable. It is this second factor which is responsible for the second law in thermodynamics, and the small T-violation in the first factor cannot significantly influence the dominating effect of the second factor.
     
  6. Jul 29, 2015 #5
    Agreed, but still you will be able to create perpetuum mobile of the second kind, right?
     
  7. Jul 29, 2015 #6

    Demystifier

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    Perhaps only far small mesoscopic systems.
     
  8. Jul 29, 2015 #7
    with respect to post #4

    Is the partition of the phase space a direct result of the SM?

    If I understand correctly the apparent structure of the SM gives it a specific phase space partitioning that sets egodic probabilities, but from what is that structure defined? Is its definition considered information?
     
    Last edited: Jul 30, 2015
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