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Cr and lr circuits help exam in a bit and i'm stuck

  • Engineering
  • Thread starter frixis
  • Start date
19
0
cr and lr circuits help.. exam in a bit and i'm stuck!!!

okay so here's my question :
how is the peak voltage across the resistance (in a cr circuit) or the induction (in an rl circuit) = [tex]\pm[/tex]V[tex]_{m}[/tex]/(1-e[tex]^{-T/2\tau}[/tex])

V[tex]_{m}[/tex] is the max voltage of the pulse train.
the m denotes max

both circuits are in a steady state with a pulse response

if it were a positive step then v=V[tex]_{m}[/tex]e[tex]^{-T/\tau}[/tex]
and if it were a negative step it would be v=-V[tex]_{m}[/tex]e[tex]^{-T/\tau}[/tex]

so from this i can gather that the peak values will be a plus minus thing..
i can get to peak voltage = V[tex]_{m}[/tex]-v
but apart from that i'm very very lost... i've been working on this for a long while now but...
help please
 

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