Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Cramer's Rule

  1. Dec 3, 2006 #1
    Can someone tell me if I did this right because my solution seems wrong, but I've done it a couple times and get the same answer. I'm given the following:
    x' + 2y' + x = 0
    x' - y' + y = 1
    and the initial values of x(0) = 0 and y(0) = 1
    The idea is to solve this initial value problem.

    Can someone please tell me if this is right? Thanks.
     
  2. jcsd
  3. Dec 4, 2006 #2

    HallsofIvy

    User Avatar
    Science Advisor

    That's not at all the way I would do the problem (I detest "Laplace transform") but that's exactly what I got as the answer: x(t)= 0 and y(1)= 1. Of course, you could have checked that yourself. Since x and y are constants, there derivatives are 0 and the equations reduce to 0+ 2(0)+ 0= 0 and 0- 0+ 1= 1.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook




Loading...
Similar Threads for Cramer's Rule Date
I Chain rule found in MIT video Jul 14, 2016
Chain rule Jan 23, 2016
Differential equations and Cramer's rule Apr 16, 2014
Cramer's Rule application in differential equations Jun 2, 2012