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Crate motion question

  1. Jul 7, 2006 #1
    Just wanted to make sure if I did this right:

    Two crates of mass 12kg and 20kg are pushed across a smooth floor together, the 20kg crate in front of the 12kg crate. Their acceleration is 1.75m/s^2. What is the action reaction force between the crates?

    F=ma
    F=(32)(1.75)
    F=56N

    then F for the 12kg block = 21N, 56-21=35N, therefore the force between the crates is 35N
     
  2. jcsd
  3. Jul 7, 2006 #2

    arildno

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    It is not "F", the applied force on the 12kg crate that is 21N. The applied force F on this crate is 56N!!

    However, m*a for the 12kg crate equals 21N, and hence, the reaction force R between the two crates has magnitude 56N-21N=35N
     
  4. Jul 7, 2006 #3
    Hi Hollysmoke,
    Since the 20 kg crate is in front of the 12 kg crate, the 12kg crate must push the other crate with a force that is sufficient to communicate an acceleration of 1.75 m/s^2.
    Force that must act on the 20 kg crate must be equal to it's mass times its acceleration = 20kg x 1.75 m/s^2 = 35N.

    bye
     
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