1. The problem statement, all variables and given/known data A crate is pulled up a rough incline. The pulling force is parallel to the incline. The crate is pulled a distance of 5.79 m. The acceleration of gravity is 9.8 m/s^2 theta=23.4 degrees mass= 8.91kg Force pulling on box= 142N coefficient of friction= 0.292 Initial velocity of box= 1.48m/s A.What is the magnitude of the work is done by the gravitational force? Answer in units of J. B.How much work is done by the 142 N force? Answer in units of J. 2. Relevant equations PE= mgh W=F*displacement*cos(theta) 3. The attempt at a solution A. I tried using the mgh formula but height is not given. Then, I tried the second formula given but I do not know how to calculate the displacement. B. Used the second equation got W= 142N*5.79*cos(23.4). Ended up being incorrect. UPDATE: got the second one as the cos(theta) ended up being 1 as the angle between the displacement and the force was 0. Clearly lost. I do not know where to properly start so a hint at that would be helpful!