Hi! Here's my question on finding arc length. If I've taken the derivative correctly, is there anyway I can simplify it before putting it into the arc length formula?(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

Find the arc length where 0[tex]\leq[/tex]x[tex]\leq[/tex]2

y=(x[tex]^{3}[/tex]/3)+x[tex]^{2}[/tex]+x+1/(4x+4)

2. Relevant equations

L=[tex]\int[/tex]ds=[tex]\sqrt{1+(dy/dx)^{2}}[/tex]

3. The attempt at a solution

I've only taken the derivative so far:

(dy/dx)=x[tex]^{2}[/tex]+2x+1-4(4x+4)[tex]^{-2}[/tex]

=(x+1)[tex]^{2}[/tex]-4(4x+4)[tex]^{-2}[/tex]

I tried expanding the equation, but that only makes it more complex.

I know to find the arc length I need to square the derivative and place it in the formula (and possibly using substitution), but I'm just wondering how I can simplify the above equation to make it easier to square and calculate!

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# Homework Help: Crazy Function for Arc Length!

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