For creation operator of hamonic oscillator, we have(adsbygoogle = window.adsbygoogle || []).push({});

[tex]a^\dagger |n> = \sqrt{n+1}|n+1>[/tex]

if I consider the creation operator operate on the bar vector, should I also get the same thing? namely

[tex]<n|a^\dagger = \sqrt{n+1}<n+1|[/tex]

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# Creation operator

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