Suppose a problem requires me to find the result of [(a+a#)^n ]ln> , where a is the annhilation operator , and a# is the creation operator , now n can be any number , suppose if it is 10 then will i write (a+a#) 10 times and then multiply each of these terms to see which are non zero , isn't there some general form of getting result of (a+a#)^n ?(adsbygoogle = window.adsbygoogle || []).push({});

The normal method of multiplying will become too cumbersome if n is a large number .

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# Creation operator

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