1. Mar 9, 2010 #1

   mkbh_10

   

   Suppose a problem requires me to find the result of [(a+a#)^n ]ln> , where a is the annhilation operator , and a# is the creation operator , now n can be any number , suppose if it is 10 then will i write (a+a#) 10 times and then multiply each of these terms to see which are non zero , isn't there some general form of getting result of (a+a#)^n ?
   
   The normal method of multiplying will become too cumbersome if n is a large number .

    

   mkbh_10, Mar 9, 2010
2. 
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3. Mar 9, 2010 #2

   f95toli

   

   Science Advisor

   Gold Member

   Why not simply use Pascal's triangle?
   
   edit: just realized that this might not actually works since the operators do not commute...

    

   f95toli, Mar 9, 2010

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