1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Critical number

  1. Mar 29, 2009 #1
    1. The problem statement, all variables and given/known data

    Determine the values of the number "a" for which the function "f" has no critical number.

    2. Relevant equations
    If I'm not mistaken, this should be the result for differentiation:

    3. The attempt at a solution

    Critical points are either where function derivation is not defined (does not exists), OR where the derivation is equal to zero.
    This is my answer; although, it seems to be a very complicated and somehow incorrect:

    "a" should not be these values, so "f" will not have any critical number.
    Last edited by a moderator: Nov 29, 2012
  2. jcsd
  3. Mar 29, 2009 #2


    User Avatar
    Science Advisor

    No, a is a constant not function of x!

    As you say, a "critical point" is one where [itex]f'(x)= -2(a^2+a- 6)sin(2x)+ a- 2[/itex] does not exist or is 0. That exists for all a and is 0 when
    [tex]-2(a^2+ a- 6)sin(2x)+ a- 2= 0[/itex]
    [tex]sin(2x)= \frac{a-2}{-2(a^2+ + a- 2)}[/itex]
    That never happens if
    [tex]\frac{a-2}{-2(a^2+ a- 2)}> 1[/itex]
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook