1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Critical numbers

  1. Nov 11, 2005 #1
    Im supposed to find the critical numbers for the function:
    F(x)= x^3-12x^2
    I think I did it right I just needed some reassurance, I got
    F'(x)= 3x^2-24
    =3x=0 and x-8=0

    so the critcal numbers are x=0 and x=8 I think:shy: I hope someone can tell me if I did this right

  2. jcsd
  3. Nov 11, 2005 #2


    User Avatar
    Homework Helper

    yes, correct [save typo F'(x)= 3x^2-24x = 3x(x-8)]
  4. Nov 11, 2005 #3
    Thank you I might need more help later
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook