1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Critical numbers

  1. Nov 11, 2005 #1
    Im supposed to find the critical numbers for the function:
    F(x)= x^3-12x^2
    I think I did it right I just needed some reassurance, I got
    F'(x)= 3x^2-24
    =3x=0 and x-8=0

    so the critcal numbers are x=0 and x=8 I think:shy: I hope someone can tell me if I did this right

  2. jcsd
  3. Nov 11, 2005 #2


    User Avatar
    Homework Helper

    yes, correct [save typo F'(x)= 3x^2-24x = 3x(x-8)]
  4. Nov 11, 2005 #3
    Thank you I might need more help later
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Critical numbers
  1. Critical number (Replies: 1)

  2. Critical Numbers (Replies: 4)