1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Critical point

  1. Nov 20, 2003 #1
    V(x) = x(10-2x)(16-2x)

    When i V'(x) = 0... x is always a non real number... I don't know why, can someone help me thanks.
     
  2. jcsd
  3. Nov 21, 2003 #2

    ShawnD

    User Avatar
    Science Advisor

    V(x) = (10x-2x^2)(16-2x)
    V(x) = 160x - 20x^2 - 32x^2 + 4x^3
    V(x) = 160x - 52x^2 + 4x^3
    V'(x) = 160 - 104x + 12x^2
    0 = 160 - 104x + 12x^2 I don't feel like doing quadratic equation so I just graphed it
    x = 2, x = 6.6666666 (which is 20/3)

    How did you go about getting your answers?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Critical point
  1. Critical point (Replies: 2)

  2. Critical points (Replies: 6)

  3. Critical points (Replies: 4)

  4. Critical points (Replies: 2)

  5. Critical Points (Replies: 2)

Loading...