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V(x) = x(10-2x)(16-2x)
When i V'(x) = 0... x is always a non real number... I don't know why, can someone help me thanks.
When i V'(x) = 0... x is always a non real number... I don't know why, can someone help me thanks.
V(x) = (10x-2x^2)(16-2x)Originally posted by PrudensOptimus
V(x) = x(10-2x)(16-2x)
When i V'(x) = 0... x is always a non real number... I don't know why, can someone help me thanks.