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A Critical temperature for bubble nucleation

  1. May 11, 2017 #1
    Consider that the criterion for bubble nucleation (in a field theory) is the following:

    $$\exp(-S_{3}/T) \gtrsim \frac{3}{4\pi} \left(\frac{H}{T}\right)^{4} \left(\frac{2\pi T}{S_{3}}\right)^{3/2},$$

    where ##S_3## is the three-dimensional action of the theory and ##H## is the Hubble scale.

    1. What is meant by the critical temperature of bubble nucleation?

    2. Why does taking the derivative of this criterion give us the critical temperature for bubble nucleation?

    N.B. : The critical temperature ##T_c## for bubble nucleation is ##T_{c} = (2/11)S_{3}##.
     
  2. jcsd
  3. May 17, 2017 #2
    Thanks for the thread! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post? The more details the better.
     
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