Critical values and linear least squares

  • Thread starter sam.pat
  • Start date
  • #1
6
0
I have a question about Linear least squares:

In Linear least squares, For any critical point "x" it must follow the linear system:
A(Transpose) * Ax = b * A(Transpose) where x is the critical point.

But here x is an n vector, so does that mean there are as many critical points (x) as there are columns?

So in case of an quadratic polynomial : 1 + X2*t + X3*t^2 with three parameters, would we have three critical points?

|1 t1 t1^2 |
|1 t2 t2^2 |
|1 t3 t3^3 |
|1 ... ..... |
|1 ... ..... |

Thanks in advance
 

Answers and Replies

Related Threads on Critical values and linear least squares

  • Last Post
Replies
0
Views
2K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
11
Views
3K
Replies
1
Views
3K
Replies
2
Views
1K
  • Last Post
Replies
13
Views
3K
  • Last Post
Replies
1
Views
2K
Replies
3
Views
1K
Replies
0
Views
2K
Top