Hello Everyone, I'm doing a question on critical values and absolute max and mins and for some stupid reason I can't seem to get one of the questions that was assigned. Find the absolute max and/or min of the (cube root t )(8-t) in the closed interval [0,8] First to solve this found the first derivative so that I could find the critical numbers of the equation, which is where the first derivative equals zero. So when I found the first derivative I got ((1/3)(8-t)-t^(2-3))/(cube root t) Now I know that one of these critical values is obviously going to be at t=0. But I'm stumped when it comes to finding the critical number from the numerator. I know this is a really stupid question, but I just can't seem to figure it out. Thanks in advance for any advice you can give.